Mutamin's Challenge - YUAN-TI

[Papago]

I'm at the Yuan-Ti's riddle in Mutamin's Challenge. I've successfully
passed the first riddle, but the second one doesn't make sense. Here's the
synopsis if you've forgotten:

Some trinkets are being divided between less than 10 girls. As it is it can
be divided evenly, but the girls have an argument and some want to divide by
family instead of by individual. If they divide by family, they get 5 more
trinkets per family. There are 2 groups of 2 sisters, the rest are
unrelated.

The shares in the trinkets become even again when one girl steps out and
says she doesn't want any treasure.


Okay, straightforward enough so far, but none of the answers I'm given match
the criteria! For this to work, the original number of girls must be evenly
divisible by the amount of trinkets. However, none of the answers supply
that possibility!

I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.

You can't equally divide 12 trinkets up between 5 girls! Was this a mistake
by the programmers???

[John Salerno]

Post by Papago
I'm at the Yuan-Ti's riddle in Mutamin's Challenge. I've successfully
passed the first riddle, but the second one doesn't make sense. Here's the
Some trinkets are being divided between less than 10 girls. As it is it can
be divided evenly, but the girls have an argument and some want to divide by
family instead of by individual. If they divide by family, they get 5 more
trinkets per family. There are 2 groups of 2 sisters, the rest are
unrelated.
The shares in the trinkets become even again when one girl steps out and
says she doesn't want any treasure.
Okay, straightforward enough so far, but none of the answers I'm given match
the criteria! For this to work, the original number of girls must be evenly
divisible by the amount of trinkets. However, none of the answers supply
that possibility!
I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.
You can't equally divide 12 trinkets up between 5 girls! Was this a mistake
by the programmers???

I had a hell of time with this too, and eventually I just gave the wrong
answer and killed the Yuan-Ti. I'd have to have the exact wording of the
riddle again, though, because I'd like to figure out eventually for myself.

[Hans Wein]

Post by Papago
I'm at the Yuan-Ti's riddle in Mutamin's Challenge. I've successfully
passed the first riddle, but the second one doesn't make sense.
Some trinkets are being divided between less than 10 girls. As it is
it can be divided evenly, but the girls have an argument and some
want to divide by family instead of by individual. If they divide by
family, they get 5 more trinkets per family. There are 2 groups of 2
sisters, the rest are unrelated.
The shares in the trinkets become even again when one girl steps out
and says she doesn't want any treasure.
Okay, straightforward enough so far, but none of the answers I'm
given match the criteria! For this to work, the original number of
girls must be evenly divisible by the amount of trinkets. However,
none of the answers supply that possibility!
I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.
You can't equally divide 12 trinkets up between 5 girls! Was this a
mistake by the programmers???

No, your walkthrough seems to be a bit incomplete. The German version of NWN
says "xx trinkets for *each* girl" in the conversation lines, which means a
total amount of 60.

Hans

[Barry Scott Will]

Post by Papago
I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.
You can't equally divide 12 trinkets up between 5 girls! Was this a mistake
by the programmers???

That's 5 girls *after* one has declined a share. When looking at the
answers, you have to add one to the number of girls to see if it matches
the first criteria (evenly divided into). So there were originally 6
girls and 12 trinkets.

[Papago]

Post by Barry Scott Will
That's 5 girls *after* one has declined a share. When looking at the
answers, you have to add one to the number of girls to see if it matches
the first criteria (evenly divided into). So there were originally 6
girls and 12 trinkets.

Well, if that's the case then it should have specified that it's *after* the
girl has declined her share. Otherwise you just naturally assume they're
asking how many girls there were to begin with.

[Barry Scott Will]

Post by Papago
Well, if that's the case then it should have specified that it's *after* the
girl has declined her share. Otherwise you just naturally assume they're
asking how many girls there were to begin with.

Sorry, that was a mistake. You must have caught it quick, because I
cancelled the post. Hans got it right. It's 12 trinkets *per* girl. 5 x
12 = 60 trinkets. Before there were 6 girls getting 10 trinkets each.
And it does very clearly ask you to tell how many girls actually
received a share (i.e. after one had declined) and how many each girl
received.

[mindseye]

I don't remember this riddle, because I haven't gotten that far - but it
does make sense.

Remember, you're answering the question AFTER the one girl has left. BEFORE
she left, it was 12 trinkets and 6 girls - 12/6 = 2. AFTER the girl left,
then it's 12 and five, but one girl is getting an extra because of her
family connection, so it still divides nicely.

- Blayde

Post by Papago
I'm at the Yuan-Ti's riddle in Mutamin's Challenge. I've successfully
passed the first riddle, but the second one doesn't make sense. Here's the
Some trinkets are being divided between less than 10 girls. As it is it can
be divided evenly, but the girls have an argument and some want to divide by
family instead of by individual. If they divide by family, they get 5 more
trinkets per family. There are 2 groups of 2 sisters, the rest are
unrelated.
The shares in the trinkets become even again when one girl steps out and
says she doesn't want any treasure.
Okay, straightforward enough so far, but none of the answers I'm given match
the criteria! For this to work, the original number of girls must be evenly
divisible by the amount of trinkets. However, none of the answers supply
that possibility!
I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.
You can't equally divide 12 trinkets up between 5 girls! Was this a mistake
by the programmers???

[DerBatz.]

Post by Papago
I'm at the Yuan-Ti's riddle in Mutamin's Challenge. I've successfully
passed the first riddle, but the second one doesn't make sense. Here's the
Some trinkets are being divided between less than 10 girls. As it is it can
be divided evenly, but the girls have an argument and some want to divide by
family instead of by individual. If they divide by family, they get 5 more
trinkets per family. There are 2 groups of 2 sisters, the rest are
unrelated.
The shares in the trinkets become even again when one girl steps out and
says she doesn't want any treasure.
Okay, straightforward enough so far, but none of the answers I'm given match
the criteria! For this to work, the original number of girls must be evenly
divisible by the amount of trinkets. However, none of the answers supply
that possibility!
I've looked up the answer in a walkthrough online, apparently it's 12
trinkets and 5 girls.
You can't equally divide 12 trinkets up between 5 girls! Was this a mistake
by the programmers???

It baffled me too so I just Zapped her.